ГДЗ ГДЗ Математика 5 класс учебник Мерзляк, Полонский - Номера упражнений - 1056
Задание:
Номер 1056.
Найдите:
Номер 1056.
Выполните умножение:
Решение:
- \(9\frac{3}{7}\cdot \frac{5}{22}\)
$$ 9\frac{3}{7}=\frac{66}{7} $$
$$ \frac{66}{7}\cdot \frac{5}{22}=\frac{3\cdot 5}{7}=\frac{15}{7}=2\frac{1}{7} $$
- \(6\frac{3}{8}\cdot \frac{16}{17}\)
$$ 6\frac{3}{8}=\frac{51}{8} $$
$$ \frac{51}{8}\cdot \frac{16}{17}=\frac{3\cdot 16}{8}=\frac{48}{8}=6 $$
- \(2\frac{1}{3}\cdot 1\frac{1}{5}\)
$$ 2\frac{1}{3}=\frac{7}{3},\qquad 1\frac{1}{5}=\frac{6}{5} $$
$$ \frac{7}{3}\cdot \frac{6}{5}=\frac{14}{5}=2\frac{4}{5} $$
- \(19\frac{1}{2}\cdot 1\frac{5}{9}\)
$$ 19\frac{1}{2}=\frac{39}{2},\qquad 1\frac{5}{9}=\frac{14}{9} $$
$$ \frac{39}{2}\cdot \frac{14}{9}=\frac{91}{3}=30\frac{1}{3} $$
- \(2\frac{1}{4}\cdot 2\frac{2}{27}\)
$$ 2\frac{1}{4}=\frac{9}{4},\qquad 2\frac{2}{27}=\frac{56}{27} $$
$$ \frac{9}{4}\cdot \frac{56}{27}=\frac{14}{3}=4\frac{2}{3} $$
- \(2\frac{8}{11}\cdot 5\frac{2}{15}\)
$$ 2\frac{8}{11}=\frac{30}{11},\qquad 5\frac{2}{15}=\frac{77}{15} $$
$$ \frac{30}{11}\cdot \frac{77}{15}=14 $$
- \(\frac{7}{9}\cdot 1\frac{1}{14}\cdot 5\frac{2}{5}\)
$$ 1\frac{1}{14}=\frac{15}{14},\qquad 5\frac{2}{5}=\frac{27}{5} $$
$$ \frac{7}{9}\cdot \frac{15}{14}\cdot \frac{27}{5} = \frac{9}{2}=4\frac{1}{2} $$
- \(2\frac{2}{3}\cdot 1\frac{1}{24}\cdot 5\frac{2}{5}\)
$$ 2\frac{2}{3}=\frac{8}{3},\qquad 1\frac{1}{24}=\frac{25}{24},\qquad 5\frac{2}{5}=\frac{27}{5} $$
$$ \frac{8}{3}\cdot \frac{25}{24}\cdot \frac{27}{5}=15 $$
Ответ
- \(2\frac{1}{7}\)
- \(6\)
- \(2\frac{4}{5}\)
- \(30\frac{1}{3}\)
- \(4\frac{2}{3}\)
- \(14\)
- \(4\frac{1}{2}\)
- \(15\)